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 PERSAMAAN LOGARITMA |
| Jumat, 13 Juni 2008 |
alog f(x) = alog g(x) ® f(x) = g(x)
alog f(x) = b ® f(x) =ab
f(x)log a = b ® (f(x))b = a
Dengan syarat x yang didapat dari persamaan tersebut harus terdefinisi.
(Bilangan pokok > 0 ¹ 1 dan numerus > 0 )
Contoh:
Tentukan nilai x yang memenuhi persamaan berikut !
x log 1/100 = -1/8
x-1/8 = 10-2
(x -1/8) -8 = (10-2)-8
x = 10 16
xlog 81 - 2 xlog 27 + xlog 9 + 1/2 xlog 729 = 6
xlog 34 - 2 xlog33 + xlog² + 1/2 xlog 36 = 6
4 xlog3 - 6 xlog3 + 2 xlog3 + 3 xlog 3 = 6
3 xlog 3 = 6
xlog 3 = 2
x² = 3 ® x
= Ö3 (x>0)
xlog (x+12) - 3 xlog4 + 1 = 0
xlog(x+12) - xlog 4³ = -1
xlog ((x+12)/4³) = -1
(x+12)/4³ = 1/x
x² + 12x - 64 = 0
(x + 16)(x - 4) = 0
x = -16 (TM) ; x = 4
²log²x - 2 ²logx - 3 = 0
misal : ²log x = p
p² - 2p - 3 = 0
(p-3)(p+1) = 0
p1 = 3
²log x = 3
x1 = 2³ = 8
p2 = -1²log x = -1
x2 = 2-1 = 1/2
Bilangan pokok a > 0 ¹ 1 |
posted by Theraphi Otak Dengan Matematika @ 22.31  |
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Name:Niko Hariyadi
Home: Bandar Lampoeng
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